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Saturday, 31 October

JEE Main 2024 · PhysicsMultiple choiceSingle correctEasyApplication

JEE Main 27 January 2024, Shift 1, Physics Q32

Question 32 of 90 in this shift, Physics question 2 of 30, Section A.

Position of an ant (S in metres) moving in Y-Z plane is given by S=2t2j^+5k^S = 2t^2\hat{j} + 5\hat{k} (where t is in second). The magnitude and direction of velocity of the ant at t = 1 s will be :
  1. (1)4 m/s in xx-direction
  2. (2)16 m/s in yy-direction
  3. (3)4 m/s in yy-directionOfficial answer
  4. (4)9 m/s in zz-direction

Official answer

Option 3

NTA final key.

Same idea in other shifts

Asked 2× in all
  1. 16 Mar 2021, Shift 2 · Q16A mosquito is moving with a velocity v⃗=0.5 t2i^+3tj^+9k^\vec{v}=0.5\,t^2\hat{i}+3t\hat{j}+9\hat{k} m/s and accelerating in uniform conditions. What will be…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.