JEE Main 2024 · MathsNumerical answerNumerical valueMediumCalculation

JEE Main 27 January 2024, Shift 1, Maths Q24

Question 24 of 90 in this shift, Maths question 24 of 30, Section B.

8=3+\dfrac{1}{4}(3+p)+\dfrac{1}{4^2}(3+2p)+\dfrac{1}{4^3}(3+3p)+\cdots\cdots\infty

, then the value of p is ________.

Official answer

NTA final key.

Chapter: Sequences and Series
Topic: Arithmetico-Geometric Series
Idea tested: Sum of Infinite AGP

Same idea in other shifts

Asked 5× in all

3 Apr 2025, Shift 2 · Q8If the probability that the random variable $X$ takes the value $x$ is given by $P(X = x) = k(x + 1)3^{-x},\ x = 0, 1, 2, 3\ldots$ , where…MediumSingle correct
29 Jul 2022, Shift 1 · Q24Let $a_1, a_2, a_3, \ldots$ be an A.P. If $\sum_{r=1}^{\infty} \frac{a_r}{2^r} = 4$ , then $4a_2$ is equal to __________.MediumNumerical value
26 Feb 2021, Shift 1 · Q78The sum of the infinite series $1+\frac{2}{3}+\frac{7}{3^2}+\frac{12}{3^3}+\frac{17}{3^4}+\frac{22}{3^5}+\ldots\ldots$ is equal to :EasySingle correct
25 Jul 2021, Shift 1 · Q84If the value of…MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.