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Saturday, 31 October

JEE Main 2024 · ChemistryMultiple choiceOtherMediumMulti-step

JEE Main 1 February 2024, Shift 2, Chemistry Q78

Question 78 of 90 in this shift, Chemistry question 18 of 30, Section A.

C2H5Br→alc. KOHA→CCl4Br2B→ExcessKCNC→ExcessH3O+D\mathrm{C_2H_5Br \xrightarrow{alc.\ KOH} A \xrightarrow[CCl_4]{Br_2} B \xrightarrow[Excess]{KCN} C \xrightarrow[Excess]{H_3O^+} D} Acid D formed in above reaction is :

The figure, in words

Reaction scheme: C2H5Br with alc. KOH gives A; A with Br2/CCl4 gives B; B with excess KCN gives C; C with excess H3O+ (arrow drawn downward from C) gives D.
  1. (1)Oxalic acid
  2. (2)Malonic acid
  3. (3)Gluconic acid
  4. (4)Succinic acidOfficial answer

Official answer

Option 4

NTA final key.

Chapter
Haloalkanes and Haloarenes
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.