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Saturday, 31 October

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JEE Main 2024 · MathsMultiple choiceSingle correctMediumCalculation

JEE Main 1 February 2024, Shift 2, Maths Q6

Question 6 of 90 in this shift, Maths question 6 of 30, Section A.

Let

m

and

n

be the coefficients of seventh and thirteenth terms respectively in the expansion of

\left(\frac{1}{3}x^{\frac{1}{3}}+\frac{1}{2x^{\frac{2}{3}}}\right)^{18}

. Then

\left(\frac{n}{m}\right)^{\frac{1}{3}}

is :

(1) $\frac{1}{4}$
(2) $\frac{1}{9}$
(3) $\frac{4}{9}$
(4) $\frac{9}{4}$ Official answer

Official answer

Option 4

NTA final key.

Chapter: Binomial Theorem
Topic: No close match in our taxonomy
Idea tested: No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.