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Saturday, 31 October

JEE Main 2024 · MathsMultiple choiceSingle correctMediumApplication

JEE Main 1 February 2024, Shift 2, Maths Q3

Question 3 of 90 in this shift, Maths question 3 of 30, Section A. NTA dropped this question from the final key; it is left out of every count on this site.

If zz is a complex number such that ∣z∣≥1|z|\geq 1, then the minimum value of ∣z+12(3+4i)∣\left|z+\frac{1}{2}(3+4i)\right| is :
  1. (1)32\frac{3}{2}
  2. (2)22
  3. (3)52\frac{5}{2}
  4. (4)33

Official answer

Dropped by NTA (marks given to all)

NTA final key: NTA final key: Drop (question dropped).

Same idea in other shifts

Asked 8× in all
  1. 2 Apr 2026, Shift 2 · Q2Let the circles C1:∣z∣=rC_1: |z| = r and C2:∣z−3−4i∣=5,z∈CeC_2: |z - 3 - 4i| = 5, z \in \mathbb{C}_e be such that C2C_2 lies within C1C_1. If z1z_1 moves on…MediumSingle correct
  2. 2 Apr 2025, Shift 1 · Q2Let zz be a complex number such that ∣z∣=1|z|=1. If 2+k2zk+zˉ=kz\frac{2+k^2z}{k+\bar{z}}=kz, k∈Rk\in\mathbf{R}, then the maximum distance of k+ik2k+ik^2…HardSingle correct
  3. 9 Apr 2024, Shift 2 · Q2Let zz be a complex number such that the real part of z−2iz+2i\frac{z-2i}{z+2i} is zero. Then, the maximum value of ∣z−(6+8i)∣|z-(6+8i)| is equal toMediumSingle correct
  4. 1 Feb 2024, Shift 1 · Q22Let P={z∈C:∣z+2−3i∣≤1}P=\{z\in\mathbb{C}:|z+2-3i|\leq1\} and Q={z∈C:z(1+i)+zˉ(1−i)≤−8}Q=\{z\in\mathbb{C}:z(1+i)+\bar{z}(1-i)\leq-8\}. Let in P∩QP\cap Q, ∣z−3+2i∣|z-3+2i| be maximum and…HardNumerical value
  5. 25 Jul 2022, Shift 2 · Q1For z∈Cz \in \mathbb{C} if the minimum value of (∣z−32∣+∣z−p2i∣)\left(\left|z-3\sqrt{2}\right|+\left|z-p\sqrt{2}i\right|\right) is 525\sqrt{2}, then a…MediumSingle correct
  6. 28 Jul 2022, Shift 1 · Q15Let S1={z1∈C:∣z1−3∣=12}S_1=\left\{z_1\in\mathbf{C}:|z_1-3|=\frac{1}{2}\right\} and S2={z2∈C:∣z2−∣z2+1∣∣=∣z2+∣z2−1∣∣}S_2=\{z_2\in\mathbf{C}:|z_2-|z_2+1||=|z_2+|z_2-1||\}. Then, for…HardSingle correct
  7. 29 Jul 2022, Shift 2 · Q1If z≠0z\neq 0 be a complex number such that ∣z−1z∣=2\left|z-\frac{1}{z}\right|=2, then the maximum value of ∣z∣|z| is :MediumSingle correct
  8. 26 Feb 2021, Shift 2 · Q82Let zz be those complex numbers which satisfy ∣z+5∣≤4|z+5| \le 4 and z(1+i)+z‾(1−i)≥−10z(1+i)+\overline{z}(1-i) \ge -10, i=−1i=\sqrt{-1}. If the maximum value…HardNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.