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Saturday, 31 October

JEE Main 2024 · MathsMultiple choiceSingle correctMediumCalculation

JEE Main 1 February 2024, Shift 2, Maths Q16

Question 16 of 90 in this shift, Maths question 16 of 30, Section A.

Let PP and QQ be the points on the line x+38=y−42=z+12\frac{x+3}{8}=\frac{y-4}{2}=\frac{z+1}{2} which are at a distance of 66 units from the point R(1,2,3)R(1,2,3). If the centroid of the triangle PQRPQR is (α,β,γ)(\alpha,\beta,\gamma), then α2+β2+γ2\alpha^2+\beta^2+\gamma^2 is :
  1. (1)1818Official answer
  2. (2)2424
  3. (3)2626
  4. (4)3636

Official answer

Option 1

NTA final key.