JEE Main 2024 · PhysicsNumerical answerNumerical valueEasyCalculation

JEE Main 1 February 2024, Shift 1, Physics Q52

Question 52 of 90 in this shift, Physics question 22 of 30, Section B.

The identical spheres each of mass 2M are placed at the corners of a right angled triangle with mutually perpendicular sides equal to 4 m each. Taking point of intersection of these two sides as origin, the magnitude of position vector of the centre of mass of the system is

\frac{4\sqrt{2}}{x}

, where the value of

x

is ________

Official answer

NTA final key.

Chapter: System of Particles and Rotational Motion
Topic: Center of Mass
Idea tested: Discrete System COM

Same idea in other shifts

Asked 5× in all

6 Apr 2026, Shift 1 · Q33The position of center of mass of three masses 2 kg, 3 kg and 15 kg placed with respect to mid point ( $p$ ) of normal bisector, as shown in…EasySingle correctHas a figure
25 Jul 2022, Shift 2 · Q52Three identical spheres each of mass M are placed at the corners of a right angled triangle with mutually perpendicular sides equal to 3 m…EasyNumerical value
29 Jul 2022, Shift 1 · Q36Two bodies of mass 1 kg and 3 kg have position vectors $\hat{i} + 2\hat{j} + \hat{k}$ and $-3\hat{i} - 2\hat{j} + \hat{k}$ respectively.…EasySingle correct
27 Jun 2022, Shift 1 · Q35Two blocks of masses 10 kg and 30 kg are placed on the same straight line with coordinates $(0, 0)$ cm and $(x, 0)$ cm respectively. The…EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.