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Friday, 9 October

JEE Main 2024 · PhysicsNumerical answerNumerical valueEasyCalculation

JEE Main 9 April 2024, Shift 2, Physics Q57

Question 57 of 90 in this shift, Physics question 27 of 30, Section B.

A particle of mass 0.500.50 kg executes simple harmonic motion under force F=−50 (Nm−1)xF=-50\ (Nm^{-1})x. The time period of oscillation is x35\frac{x}{35} s. The value of xx is __________. (Given π=227\pi=\frac{22}{7})

Official answer

22

NTA final key.

Chapter
Oscillations
Topic
SHM Equations
Idea tested
SHM Definition and Force Law

Same idea in other shifts

Asked 2× in all
  1. 3 Apr 2025, Shift 1 · Q36Two blocks of masses m and M, (M>m)(M > m), are placed on a frictionless table as shown in figure. A massless spring with spring constant k…HardOtherHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.