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JEE Main 2024 · PhysicsNumerical answerNumerical valueEasyCalculation

JEE Main 9 April 2024, Shift 2, Physics Q55

Question 55 of 90 in this shift, Physics question 25 of 30, Section B.

At room temperature (

27^\circ

C), the resistance of a heating element is

50\ \Omega

. The temperature coefficient of the material is

2.4\times10^{-4}\ {}^\circ C^{-1}

. The temperature of the element, when its resistance is

62\ \Omega

, is _________

^\circ

C.

Official answer

1027

NTA final key.

Chapter: Current Electricity
Topic: Ohm's Law and Resistance
Idea tested: Temperature Coefficient of Resistance

Same idea in other shifts

Asked 2× in all

8 Apr 2024, Shift 1 · Q56Resistance of a wire at $0\,^\circ$ C, $100\,^\circ$ C and $t\,^\circ$ C is found to be $10\ \Omega$ , $10.2\ \Omega$ and $10.95\ \Omega$ …MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.