Learn

Friday, 9 October

JEE Main 2024 · ChemistryMultiple choiceSingle correctMediumConceptual

JEE Main 9 April 2024, Shift 1, Chemistry Q63

Question 63 of 90 in this shift, Chemistry question 3 of 30, Section A.

0.05M CuSO40.05\mathrm{M}\ \mathrm{CuSO_4} when treated with 0.01M K2Cr2O70.01\mathrm{M}\ \mathrm{K_2Cr_2O_7} gives green colour solution of Cu2Cr2O7\mathrm{Cu_2Cr_2O_7}. The two solutions are separated as shown below : [SPM : Semi Permeable Membrane] [figure: container divided by SPM; Side X contains K2Cr2O7\mathrm{K_2Cr_2O_7}, Side Y contains CuSO4\mathrm{CuSO_4}] Due to osmosis :

The figure, in words

Rectangular container divided in two by a semipermeable membrane (SPM): left compartment Side X holds K2Cr2O7, right compartment Side Y holds CuSO4.
  1. (1)Green colour formation observed on side Y.
  2. (2)Green colour formation observed on side X.
  3. (3)Molarity of K2Cr2O7\mathrm{K_2Cr_2O_7} solution is lowered.
  4. (4)Molarity of CuSO4\mathrm{CuSO_4} solution is lowered.Official answer

Official answer

Option 4

NTA final key.

Chapter
Solutions
Topic
Colligative Properties
Idea tested
Hypertonic and Hypotonic Solutions

Same idea in other shifts

Asked 2× in all
  1. 4 Apr 2026, Shift 2 · Q54At 27 ∘^\circC, 0.1 M, 1 L K4[Fe(CN)6]\mathrm{K_4[Fe(CN)_6]} aqueous solution and 0.1 M, 1 L FeCl3\mathrm{FeCl_3} aqueous solution are placed in a…MediumSingle correctHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.