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Friday, 9 October

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JEE Main 2024 · MathsMultiple choiceSingle correctEasyCalculation

JEE Main 9 April 2024, Shift 1, Maths Q6

Question 6 of 90 in this shift, Maths question 6 of 30, Section A.

Let

f(x)=ax^3+bx^2+cx+41

be such that

f(1)=40

,

f'(1)=2

and

f''(1)=4

. Then

a^2+b^2+c^2

is equal to :

(1) $51$ Official answer
(2) $54$
(3) $62$
(4) $73$

Official answer

Option 1

NTA final key.

Chapter: Application of Derivatives
Topic: No close match in our taxonomy
Idea tested: No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.