JEE Main 2024 · PhysicsNumerical answerNumerical valueEasyMulti-step

JEE Main 9 April 2024, Shift 1, Physics Q52

Question 52 of 90 in this shift, Physics question 22 of 30, Section B.

A string is wrapped around the rim of a wheel of moment of inertia

0.40\ \mathrm{kgm^2}

and radius

10

cm. The wheel is free to rotate about its axis. Initially the wheel is at rest. The string is now pulled by a force of

40

N. The angular velocity of the wheel after

10

s is

x

rad/s, where

x

is ________.

Official answer

100

NTA final key.

Chapter: System of Particles and Rotational Motion
Topic: Torque and Equilibrium
Idea tested: Torque Calculation

Same idea in other shifts

Asked 3× in all

13 Apr 2023, Shift 2 · Q52A light rope is wound around a hollow cylinder of mass 5 kg and radius 70 cm. The rope is pulled with a force of 52.5 N. The angular…MediumNumerical value
16 Mar 2021, Shift 2 · Q24A force $\vec{F}=4\hat{i}+3\hat{j}+4\hat{k}$ is applied on an intersection point of $x=2$ plane and $x$ -axis. The magnitude of torque of…EasyNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.