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Friday, 9 October

JEE Main 2024 · PhysicsMultiple choiceSingle correctMediumMulti-step

JEE Main 9 April 2024, Shift 1, Physics Q36

Question 36 of 90 in this shift, Physics question 6 of 30, Section A.

An astronaut takes a ball of mass m from earth to space. He throws the ball into a circular orbit about earth at an altitude of 318.5318.5 km. From earth's surface to the orbit, the change in total mechanical energy of the ball is xGMem21Rex\frac{GM_em}{21R_e}. The value of xx is (take Re=6370R_e=6370 km) :
  1. (1)99
  2. (2)1010
  3. (3)1111Official answer
  4. (4)1212

Official answer

Option 3

NTA final key.

Chapter
Gravitation
Topic
Orbital Mechanics
Idea tested
Energy of Orbiting Bodies

Same idea in other shifts

Asked 2× in all
  1. 2 Apr 2025, Shift 2 · Q47A satellite of mass 1000 kg is launched to revolve around the earth in an orbit at a height of 270 km from the earth's surface. Kinetic…MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.