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Friday, 9 October

JEE Main 2024 · MathsMultiple choiceSingle correctEasyMulti-step

JEE Main 9 April 2024, Shift 1, Maths Q12

Question 12 of 90 in this shift, Maths question 12 of 30, Section A.

Let f(x)=x2+9f(x)=x^2+9, g(x)=xx−9g(x)=\frac{x}{x-9} and a=f∘g(10)a=f\circ g(10), b=g∘f(3)b=g\circ f(3). If ee and ll denote the eccentricity and the length of the latus rectum of the ellipse x2a+y2b=1\frac{x^2}{a}+\frac{y^2}{b}=1, then 8e2+l28e^2+l^2 is equal to.
  1. (1)1616
  2. (2)1212
  3. (3)88Official answer
  4. (4)66

Official answer

Option 3

NTA final key.