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Saturday, 31 October

JEE Main 2024 · MathsMultiple choiceSingle correctHardMulti-step

JEE Main 8 April 2024, Shift 2, Maths Q9

Question 9 of 90 in this shift, Maths question 9 of 30, Section A.

For a,b>0a, b > 0, let f(x)={tan⁡((a+1)x)+btan⁡xx,x<03,x=0ax+b2x2−axba xx,x>0f(x) = \begin{cases} \frac{\tan((a+1)x) + b\tan x}{x}, & x < 0 \\ 3, & x = 0 \\ \frac{\sqrt{ax + b^2x^2} - \sqrt{ax}}{b\sqrt{a}\,x\sqrt{x}}, & x > 0 \end{cases} be a continous function at x=0x = 0. Then ba\frac{b}{a} is equal to :
  1. (1)66Official answer
  2. (2)55
  3. (3)44
  4. (4)88

Official answer

Option 1

NTA final key.