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Saturday, 31 October

JEE Main 2024 · ChemistryMultiple choiceSingle correctEasyConceptual

JEE Main 8 April 2024, Shift 2, Chemistry Q65

Question 65 of 90 in this shift, Chemistry question 5 of 30, Section A.

For a reaction A→K1B→K2C\mathrm{A \xrightarrow{K_1} B \xrightarrow{K_2} C} If the rate of formation of B is set to be zero then the concentration of B is given by :
  1. (1)(K1−K2)[A](K_1 - K_2)[A]
  2. (2)K1K2[A]K_1K_2[A]
  3. (3)(K1+K2)[A](K_1 + K_2)[A]
  4. (4)(K1/K2)[A](K_1/K_2)[A]Official answer

Official answer

Option 4

NTA final key.

Same topic in other shifts

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.