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JEE Main 2024 · MathsMultiple choiceSingle correctMediumCalculation

JEE Main 8 April 2024, Shift 2, Maths Q6

Question 6 of 90 in this shift, Maths question 6 of 30, Section A.

If the term independent of

x

in the expansion of

\left(\sqrt{a}x^2 + \frac{1}{2x^3}\right)^{10}

is 105, then

a^2

is equal to :

(1) $2$
(2) $4$ Official answer
(3) $6$
(4) $9$

Official answer

Option 2

NTA final key.

Chapter: Binomial Theorem
Topic: No close match in our taxonomy
Idea tested: No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.