JEE Main 2024 (8 Apr, Shift 1) Chemistry Q84: Solutions

Question

A solution containing 10 g of an electrolyte $\mathrm{AB_2}$ in 100 g of water boils at $100.52^\circ$C. The degree of ionization of the electrolyte ($\alpha$) is __________ $	imes\ 10^{-1}$. (nearest integer)
[Given : Molar mass of $\mathrm{AB_2}$ = 200 g mol$^{-1}$, $K_b$ (molal boiling point elevation const. of water) = 0.52 K kg mol$^{-1}$, boiling point of water = $100^\circ$C ; $\mathrm{AB_2}$ ionises as $\mathrm{AB_2 ightarrow A^{2+} + 2B^-}$]

Accepted Answer

5

JEE Main 8 April 2024, Shift 1, Chemistry Q84

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