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Friday, 9 October

JEE Main 2024 · ChemistryMultiple choiceDiagram basedEasyRecall

JEE Main 8 April 2024, Shift 1, Chemistry Q79

Question 79 of 90 in this shift, Chemistry question 19 of 30, Section A.

Identify the product (P) in the following reaction: [figure: cyclopentanecarboxylic acid] →ii) H2Oi) Br2/Red P\xrightarrow[\text{ii) }\mathrm{H_2O}]{\text{i) }\mathrm{Br_2/Red\ P}} (P)

The figure, in words

Cyclopentane ring bearing COOH treated with (i) Br2/red P, (ii) H2O giving product P.
  1. (1)[figure: 1-bromocyclopentane-1-carboxylic acid (COOH\mathrm{COOH} and Br on the same ring carbon)]Official answer
  2. (2)[figure: cyclopentanecarbonyl bromide (COBr\mathrm{COBr})]
  3. (3)[figure: 2-bromocyclopentane-1-carboxylic acid]
  4. (4)[figure: 1-bromocyclopentane-1-carbaldehyde (CHO\mathrm{CHO} and Br on the same ring carbon)]

Official answer

Option 1

NTA final key.

Same idea in other shifts

Asked 2× in all
  1. 6 Apr 2023, Shift 1 · Q77Match List I with List II LIST I (Name of reaction) | LIST II (Reagent used) A. Hell-Volhard-Zelinsky reaction | I. NaOH+I2\mathrm{NaOH + I_2}…MediumMatch the list

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.