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Friday, 9 October

JEE Main 2024 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 8 April 2024, Shift 1, Maths Q5

Question 5 of 90 in this shift, Maths question 5 of 30, Section A.

The equations of two sides AB and AC of a triangle ABC are 4x+y=144x+y=14 and 3x−2y=53x-2y=5, respectively. The point (2,−43)\left(2,-\frac{4}{3}\right) divides the third side BC internally in the ratio 2:12:1. the equation of the side BC is
  1. (1)x+3y+2=0x+3y+2=0Official answer
  2. (2)x−3y−6=0x-3y-6=0
  3. (3)x+6y+6=0x+6y+6=0
  4. (4)x−6y−10=0x-6y-10=0

Official answer

Option 1

NTA final key.

Chapter
Straight Lines
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.