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Friday, 9 October

JEE Main 2024 · MathsNumerical answerNumerical valueHardMulti-step

JEE Main 8 April 2024, Shift 1, Maths Q28

Question 28 of 90 in this shift, Maths question 28 of 30, Section B.

Let a⃗=9i^−13j^+25k^\vec{a}=9\hat{i}-13\hat{j}+25\hat{k}, b⃗=3i^+7j^−13k^\vec{b}=3\hat{i}+7\hat{j}-13\hat{k} and c⃗=17i^−2j^+k^\vec{c}=17\hat{i}-2\hat{j}+\hat{k} be three given vectors. If r⃗\vec{r} is a vector such that r⃗×a⃗=(b⃗+c⃗)×a⃗\vec{r}\times\vec{a}=(\vec{b}+\vec{c})\times\vec{a} and r⃗⋅(b⃗−c⃗)=0\vec{r}\cdot(\vec{b}-\vec{c})=0, then ∣593r⃗+67a⃗∣2(593)2\frac{|593\vec{r}+67\vec{a}|^2}{(593)^2} is equal to ____________.

Official answer

569

NTA final key.