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JEE Main 2024 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 8 April 2024, Shift 1, Maths Q16

Question 16 of 90 in this shift, Maths question 16 of 30, Section A.

Let

H:\frac{-x^2}{a^2}+\frac{y^2}{b^2}=1

be the hyperbola, whose eccentricity is

\sqrt{3}

and the length of the latus rectum is

4\sqrt{3}

. Suppose the point

(\alpha,6)

,

\alpha>0

lies on

H

. If

\beta

is the product of the focal distances of the point

(\alpha,6)

, then

\alpha^2+\beta

is equal to

(1) $169$
(2) $170$
(3) $171$ Official answer
(4) $172$

Official answer

Option 3

NTA final key.

Chapter: Conic Sections
Topic: No close match in our taxonomy
Idea tested: No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.