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Friday, 9 October

JEE Main 2024 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 8 April 2024, Shift 1, Maths Q10

Question 10 of 90 in this shift, Maths question 10 of 30, Section A.

Let I(x)=∫6sin⁡2x(1−cot⁡x)2dxI(x)=\int\frac{6}{\sin^2x(1-\cot x)^2}dx. If I(0)=3I(0)=3, then I(π12)I\left(\frac{\pi}{12}\right) is equal to
  1. (1)232\sqrt{3}
  2. (2)333\sqrt{3}Official answer
  3. (3)636\sqrt{3}
  4. (4)3\sqrt{3}

Official answer

Option 2

NTA final key.

Chapter
Integrals