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Friday, 9 October

JEE Main 2024 · PhysicsMultiple choiceSingle correctMediumCalculation

JEE Main 6 April 2024, Shift 2, Physics Q49

Question 49 of 90 in this shift, Physics question 19 of 30, Section A.

The acceptor level of a p-type semiconductor is 6 eV. The maximum wavelength of light which can create a hole would be : Given hc=1242 eV nmhc=1242\ \mathrm{eV\,nm}.
  1. (1)207 nmOfficial answer
  2. (2)407 nm
  3. (3)414 nm
  4. (4)103.5 nm

Official answer

Option 1

NTA final key.

Chapter
Semiconductor Electronics: Materials, Devices and Simple Circuits
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.