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Friday, 9 October

JEE Main 2024 · MathsMultiple choiceSingle correctHardMulti-step

JEE Main 6 April 2024, Shift 2, Maths Q19

Question 19 of 90 in this shift, Maths question 19 of 30, Section A.

Let a⃗=6i^+j^−k^\vec{a}=6\hat{i}+\hat{j}-\hat{k} and b⃗=i^+j^\vec{b}=\hat{i}+\hat{j}. If c⃗\vec{c} is a vector such that ∣c⃗∣≥6|\vec{c}|\ge 6, a⃗⋅c⃗=6∣c⃗∣\vec{a}\cdot\vec{c}=6|\vec{c}|, ∣c⃗−a⃗∣=22|\vec{c}-\vec{a}|=2\sqrt{2} and the angle between a⃗×b⃗\vec{a}\times\vec{b} and c⃗\vec{c} is 60∘60^\circ, then ∣(a⃗×b⃗)×c⃗∣|(\vec{a}\times\vec{b})\times\vec{c}| is equal to :
  1. (1)323\frac{3}{2}\sqrt{3}
  2. (2)326\frac{3}{2}\sqrt{6}
  3. (3)92(6−6)\frac{9}{2}\left(6-\sqrt{6}\right)
  4. (4)92(6+6)\frac{9}{2}\left(6+\sqrt{6}\right)Official answer

Official answer

Option 4

NTA final key.