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Saturday, 31 October

JEE Main 2024 · ChemistryNumerical answerNumerical valueMediumCalculation

JEE Main 6 April 2024, Shift 1, Chemistry Q84

Question 84 of 90 in this shift, Chemistry question 24 of 30, Section B.

Consider the dissociation of the weak acid HX as given below HX(aq)⇌H+(aq)+X−(aq)\mathrm{HX(aq) \rightleftharpoons H^+(aq) + X^-(aq)}, Ka =1.2×10−5= 1.2 \times 10^{-5} [Ka\mathrm{K_a} : dissociation constant] The osmotic pressure of 0.03 M aqueous solution of HX at 300 K is __________ ×10−2\times 10^{-2} bar (nearest integer). [Given : R = 0.083 L bar mol−1^{-1} K−1^{-1}]

Official answer

76

NTA final key.

Chapter
Solutions
Idea tested
Osmotic Pressure