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Saturday, 31 October

JEE Main 2024 · PhysicsNumerical answerNumerical valueEasyCalculation

JEE Main 6 April 2024, Shift 1, Physics Q53

Question 53 of 90 in this shift, Physics question 23 of 30, Section B.

For three vectors A⃗=(−xi^−6j^−2k^)\vec{A} = (-x\hat{i} - 6\hat{j} - 2\hat{k}), B⃗=(−i^+4j^+3k^)\vec{B} = (-\hat{i} + 4\hat{j} + 3\hat{k}) and C⃗=(−8i^−j^+3k^)\vec{C} = (-8\hat{i} - \hat{j} + 3\hat{k}), if A⃗⋅(B⃗×C⃗)=0\vec{A}\cdot(\vec{B}\times\vec{C}) = 0, then value of xx is __________.

Official answer

4

NTA final key.

Chapter
Motion in a Plane
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.