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Saturday, 31 October

JEE Main 2024 · MathsMultiple choiceSingle correctMediumApplication

JEE Main 6 April 2024, Shift 1, Maths Q2

Question 2 of 90 in this shift, Maths question 2 of 30, Section A.

The function f(x)=x2+2x−15x2−4x+9f(x)=\frac{x^2+2x-15}{x^2-4x+9}, x∈Rx \in \mathbb{R} is
  1. (1)both one-one and onto.
  2. (2)one-one but not onto.
  3. (3)onto but not one-one.
  4. (4)neither one-one nor onto.Official answer

Official answer

Option 4

NTA final key.

Same idea in other shifts

Asked 2× in all
  1. 8 Apr 2024, Shift 1 · Q21If the range of f(θ)=sin⁡4θ+3cos⁡2θsin⁡4θ+cos⁡2θf(\theta)=\frac{\sin^4\theta+3\cos^2\theta}{\sin^4\theta+\cos^2\theta}, θ∈R\theta\in\mathbb{R} is [α,β][\alpha,\beta], then…MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.