JEE Main 2024 · PhysicsNumerical answerNumerical valueEasyCalculation

JEE Main 5 April 2024, Shift 2, Physics Q59

Question 59 of 90 in this shift, Physics question 29 of 30, Section B.

The current in an inductor is given by

I=(3t+8)

where t is in second. The magnitude of induced emf produced in the inductor is 12 mV. The self-inductance of the inductor ________ mH.

Official answer

NTA final key.

Chapter: Electromagnetic Induction
Topic: Inductance
Idea tested: Self-Inductance and Back EMF

Same idea in other shifts

Asked 6× in all

6 Apr 2024, Shift 2 · Q44In a coil, the current changes from $-2$ A to $+2$ A in 0.2 s and induces an emf of 0.1 V. The self inductance of the coil is :EasySingle correct
15 Apr 2023, Shift 1 · Q48A 12 V battery connected to a coil of resistance 6 $\Omega$ through a switch, drives a constant current in the circuit. The switch is…EasySingle correct
26 Jun 2022, Shift 1 · Q55A 10 $\Omega$ , 20 mH coil carrying constant current is connected to a battery of 20 V through a switch. Now after switch is opened current…EasyNumerical value
24 Feb 2021, Shift 2 · Q11Figure shows a circuit that contains four identical resistors with resistance $R = 2.0\ \Omega$ , two identical inductors with inductance…MediumDiagram basedHas a figure
9 Jan 2020, Shift 1 · Q24In a fluorescent lamp choke (a small transformer) 100 V of reverse voltage is produced when the choke current changes uniformly from 0.25…EasyNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.