JEE Main 2024 · PhysicsMultiple choiceSingle correctMediumMulti-step

JEE Main 5 April 2024, Shift 2, Physics Q46

Question 46 of 90 in this shift, Physics question 16 of 30, Section A.

A galvanometer of resistance

100\ \Omega

when connected in series with

400\ \Omega

measures a voltage of upto 10 V. The value of resistance required to convert the galvanometer into ammeter to read upto 10 A is

x\times10^{-2}\ \Omega

. The value of

x

is :

(1)20Official answer
(2)2
(3)200
(4)800

Official answer

Option 1

NTA final key.

Chapter: Moving Charges and Magnetism
Topic: Wheatstone Bridge
Idea tested: Shunting Galvanometer for Protection

Same idea in other shifts

Asked 4× in all

6 Apr 2026, Shift 2 · Q48A moving coil of galvanometer when shunted with 2 $\Omega$ resistance gives a full scale deflection for a current of 500 mA. When a…MediumNumerical value
9 Apr 2024, Shift 1 · Q50A galvanometer has a coil of resistance $200\ \Omega$ with a full scale deflection at $20\ \mu$ A. The value of resistance to be added to…EasySingle correct
29 Jan 2024, Shift 1 · Q42A galvanometer having coil resistance $10\,\Omega$ shows a full scale deflection for a current of 3mA. For it to measure a current of 8A,…EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.