JEE Main 2024 · PhysicsMultiple choiceSingle correctEasyRecall

JEE Main 5 April 2024, Shift 2, Physics Q39

Question 39 of 90 in this shift, Physics question 9 of 30, Section A.

If n is the number density and d is the diameter of the molecule, then the average distance covered by a molecule between two successive collisions (i.e. mean free path) is represented by :

(1) $\frac{1}{\sqrt{2}\,n\pi d^2}$ Official answer
(2) $\frac{1}{\sqrt{2n\pi d^2}}$
(3) $\sqrt{2}\,n\pi d^2$
(4) $\frac{1}{\sqrt{2}\,n^2\pi^2d^2}$

Official answer

Option 1

NTA final key.

Chapter: Kinetic Theory
Topic: Kinetic Theory of Gases
Idea tested: Mean Free Path

Same idea in other shifts

Asked 6× in all

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.