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Saturday, 31 October

JEE Main 2024 · ChemistryMultiple choiceDiagram basedEasyRecall

JEE Main 5 April 2024, Shift 1, Chemistry Q79

Question 79 of 90 in this shift, Chemistry question 19 of 30, Section A.

Identify 'A' in the following reaction : butan-2-one (CH3−C(=O)−CH2−CH3\mathrm{CH_3-C(=O)-CH_2-CH_3}) →(ii) ethylene glycol/KOH(i) N2H4\xrightarrow[\text{(ii) ethylene glycol/KOH}]{\text{(i) } \mathrm{N_2H_4}} 'A'

The figure, in words

Reactant drawn as skeletal formula: C=O carbonyl carbon with CH3 on one side and CH2-CH3 on the other (butan-2-one). Reagents over the arrow: (i) N2H4, (ii) ethylene glycol/KOH, giving 'A'.
  1. (1)(CH3)2C=N−NH2\mathrm{(CH_3)_2C{=}N{-}NH_2} [figure: C bearing two CH3 groups, double bonded to N-NH2]
  2. (2)[figure: butane, CH3-CH2-CH2-CH3 skeletal zigzag with terminal CH3 groups]Official answer
  3. (3)CH3(H5C2)C=N−NH2\mathrm{CH_3(H_5C_2)C{=}N{-}NH_2} [figure: C bearing CH3 and H5C2\mathrm{H_5C_2}, double bonded to N-NH2]
  4. (4)[figure: butan-2-ol, skeletal zigzag CH3-CH(OH)-CH2-CH3 with OH on the second carbon]

Official answer

Option 2

NTA final key.