JEE Main 2024 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 4 April 2024, Shift 2, Physics Q46

Question 46 of 90 in this shift, Physics question 16 of 30, Section A.

The width of one of the two slits in a Young's double slit experiment is 4 times that of the other slit. The ratio of the maximum of the minimum intensity in the interference pattern is:

(1)9:1Official answer
(2)16:1
(3)4:1
(4)1:1

Official answer

Option 1

NTA final key.

Chapter: Wave Optics
Topic: Young's Double Slit
Idea tested: Intensity Ratio from Slit Widths

Same idea in other shifts

Asked 6× in all

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25 Jun 2022, Shift 2 · Q44The interference pattern is obtained with two coherent light sources of intensity ratio 4:1. And the ratio…MediumSingle correct
30 Jun 2022, Shift 1 · Q47Find the ratio of maximum intensity to the minimum intensity in the interference pattern if the widths of the two slits in Young's…EasySingle correct
24 Feb 2021, Shift 1 · Q20In a Young’s double slit experiment, the width of the one of the slit is three times the other slit. The amplitude of the light coming…EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.