JEE Main 2024 (4 Apr, Shift 2) Physics Q32: Applying the…

Question

Applying the principle of homogeneity of dimensions, determine which one is correct,
where $T$ is time period, $G$ is gravitational constant, $M$ is mass, $r$ is radius of orbit.

Accepted Answer

Option 1: $T^2=\frac{4\pi^2 r^3}{GM}$

Answer

$T^2=\frac{4\pi^2 r^3}{GM}$

Answer

$T^2=\frac{4\pi^2 r^2}{GM}$

Answer

$T^2=4\pi^2 r^3$

Answer

$T^2=\frac{4\pi^2 r}{GM^2}$

JEE Main 4 April 2024, Shift 2, Physics Q32