JEE Main 2023 · PhysicsNumerical answerNumerical valueMediumCalculation

JEE Main 13 April 2023, Shift 2, Physics Q60

Question 60 of 90 in this shift, Physics question 30 of 30, Section B.

An atom absorbs a photon of wavelength

500

nm and emits another photon of wavelength

600

nm. The net energy absorbed by the atom in this process is

n\times10^{-4}

eV. The value of n is ______. [Assume the atom to be stationary during the absorption and emission process] (Take

h=6.6\times10^{-34}

Js and

c=3\times10^{8}

m/s).

Official answer

4125

NTA final key.

Chapter: Atoms
Topic: Photoelectric Effect
Idea tested: Photon Energy and Momentum

Same idea in other shifts

Asked 3× in all

8 Apr 2026, Shift 2 · Q38A monochromatic source of light operating at 15 kW emits $2.5 \times 10^{22}$ photons/s. The region of an electromagnetic spectrum to…MediumSingle correct
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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.