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Friday, 9 October

JEE Main 2023 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 13 April 2023, Shift 2, Physics Q32

Question 32 of 90 in this shift, Physics question 2 of 30, Section A.

The distance travelled by an object in time t is given by s=(2.5)t2s=(2.5)t^2. The instantaneous speed of the object at t=5t=5 s will be:
  1. (1)5 ms−15\ \mathrm{ms^{-1}}
  2. (2)12.5 ms−112.5\ \mathrm{ms^{-1}}
  3. (3)25 ms−125\ \mathrm{ms^{-1}}Official answer
  4. (4)62.5 ms−162.5\ \mathrm{ms^{-1}}

Official answer

Option 3

NTA final key.

Same idea in other shifts

Asked 2× in all
  1. 4 Apr 2025, Shift 2 · Q30The displacement xx versus time graph is shown below. (A) The average velocity during 0 to 3 s is 10 m/s (B) The average velocity during…MediumOtherHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.