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Friday, 9 October

JEE Main 2023 · MathsNumerical answerNumerical valueHardMulti-step

JEE Main 13 April 2023, Shift 2, Maths Q27

Question 27 of 90 in this shift, Maths question 27 of 30, Section B.

If y=y(x)y=y(x) is the solution of the differential equation dydx+4x(x2−1)y=x+2(x2−1)52\frac{dy}{dx}+\frac{4x}{(x^2-1)}y=\frac{x+2}{(x^2-1)^{\frac{5}{2}}}, x>1x>1 such that y(2)=29log⁡e(2+3)y(2)=\frac{2}{9}\log_e\left(2+\sqrt{3}\right) and y(2)=αlog⁡e(α+β)+β−γy(\sqrt{2})=\alpha\log_e\left(\sqrt{\alpha}+\beta\right)+\beta-\sqrt{\gamma}, α,β,γ∈N\alpha,\beta,\gamma\in\mathbb{N}, then αβγ\alpha\beta\gamma is equal to ______

Official answer

6

NTA final key.