JEE Main 13 April 2023, Shift 2, Maths Q24

Question 24 of 90 in this shift, Maths question 24 of 30, Section B.

Let

[\alpha]

denote the greatest integer

\le\alpha

. Then

[\sqrt{1}]+[\sqrt{2}]+[\sqrt{3}]+\ldots+[\sqrt{120}]

is equal to ______

Official answer

825

NTA final key.

Chapter: Relations and Functions
Topic: No close match in our taxonomy
Idea tested: No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.