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Friday, 9 October

JEE Main 2023 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 13 April 2023, Shift 2, Maths Q18

Question 18 of 90 in this shift, Maths question 18 of 30, Section A.

Let for a triangle ABC, AB→=−2i^+j^+3k^\overrightarrow{AB}=-2\hat{i}+\hat{j}+3\hat{k} CB→=αi^+βj^+γk^\overrightarrow{CB}=\alpha\hat{i}+\beta\hat{j}+\gamma\hat{k} CA→=4i^+3j^+δk^\overrightarrow{CA}=4\hat{i}+3\hat{j}+\delta\hat{k} If δ>0\delta>0 and the area of the triangle ABC is 565\sqrt{6}, then CB→⋅CA→\overrightarrow{CB}\cdot\overrightarrow{CA} is equal to
  1. (1)6060Official answer
  2. (2)5454
  3. (3)120120
  4. (4)108108

Official answer

Option 1

NTA final key.