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Saturday, 31 October

JEE Main 2023 · ChemistryMultiple choiceOtherMediumMulti-step

JEE Main 11 April 2023, Shift 2, Chemistry Q75

Question 75 of 90 in this shift, Chemistry question 15 of 30, Section A.

[reaction scheme: H3C−CH2−CH(OH)−CH3\mathrm{H_3C-CH_2-CH(OH)-CH_3} (butan-2-ol) →(i) NaI, H3PO4; (ii) Mg, Dry ether; (iii) D2O\xrightarrow{\text{(i) NaI, } \mathrm{H_3PO_4};\ \text{(ii) Mg, Dry ether};\ \text{(iii) } \mathrm{D_2O}} [X] Product] Product [X] formed in the above reaction is :

The figure, in words

Reaction arrow from butan-2-ol with reagents (i) NaI, H3PO4 (ii) Mg, Dry ether (iii) D2O giving product [X].
  1. (1)H3C−CH2−CH(OH)−CH3\mathrm{H_3C-CH_2-CH(OH)-CH_3} (C with H and OH)
  2. (2)H3C−CH=CH−CH3\mathrm{H_3C-CH=CH-CH_3}
  3. (3)H3C−CH2−CH(D)−CH3\mathrm{H_3C-CH_2-CH(D)-CH_3}Official answer
  4. (4)H3C−CH2−CH=CH2\mathrm{H_3C-CH_2-CH=CH_2}

Official answer

Option 3

NTA final key.

Chapter
Haloalkanes and Haloarenes
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.