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Saturday, 31 October

JEE Main 2023 · MathsMultiple choiceSingle correctMediumCalculation

JEE Main 11 April 2023, Shift 2, Maths Q5

Question 5 of 90 in this shift, Maths question 5 of 30, Section A.

If ∣x+1xxxx+λxxxx+λ2∣=98(103x+81)\begin{vmatrix} x+1 & x & x \\ x & x+\lambda & x \\ x & x & x+\lambda^2 \end{vmatrix} = \frac{9}{8}(103x + 81), then λ,λ3\lambda, \frac{\lambda}{3} are the roots of the equation
  1. (1)4x2+24x−27=04x^2 + 24x - 27 = 0
  2. (2)4x2−24x−27=04x^2 - 24x - 27 = 0
  3. (3)4x2+24x+27=04x^2 + 24x + 27 = 0
  4. (4)4x2−24x+27=04x^2 - 24x + 27 = 0Official answer

Official answer

Option 4

NTA final key.

Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.