JEE Main 2023 · MathsMultiple choiceSingle correctMediumApplication

JEE Main 11 April 2023, Shift 1, Maths Q7

Question 7 of 90 in this shift, Maths question 7 of 30, Section A.

Let

f(x) = [x^2 - x] + |-x + [x]|

, where

x \in \mathbb{R}

and

[t]

denotes the greatest integer less than or equal to

t

. Then,

f

(1)not continuous at $x=0$ and $x=1$
(2)continuous at $x=0$ and $x=1$
(3)continuous at $x=0$ , but not continuous at $x=1$
(4)continuous at $x=1$ , but not continuous at $x=0$ Official answer

Official answer

Option 4

NTA final key.

Chapter: Continuity and Differentiability
Topic: Continuity and Differentiability
Idea tested: Continuity involving GIF and Fractional Part

Same idea in other shifts

Asked 7× in all

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.