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Friday, 9 October

JEE Main 2023 · PhysicsMultiple choiceSingle correctMediumCalculation

JEE Main 11 April 2023, Shift 1, Physics Q37

Question 37 of 90 in this shift, Physics question 7 of 30, Section A.

The electric field in an electromagnetic wave is given as E⃗=20sin⁡ω(t−xc)j^ NC−1\vec{E} = 20\sin\omega\left(t - \frac{x}{c}\right)\hat{j}\ \mathrm{NC^{-1}} where ω\omega and cc are angular frequency and velocity of electromagnetic wave respectively. The energy contained in a volume of 5×10−4 m35 \times 10^{-4}\ \mathrm{m^3} will be (Given ε0=8.85×10−12 C2/Nm2\varepsilon_0 = 8.85 \times 10^{-12}\ \mathrm{C^2/Nm^2})
  1. (1)8.85×10−138.85 \times 10^{-13} JOfficial answer
  2. (2)88.5×10−1388.5 \times 10^{-13} J
  3. (3)28.5×10−1328.5 \times 10^{-13} J
  4. (4)17.7×10−1317.7 \times 10^{-13} J

Official answer

Option 1

NTA final key.

Chapter
Electromagnetic Waves
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.