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Saturday, 31 October

JEE Main 2023 · PhysicsMultiple choiceSingle correctEasyConceptual

JEE Main 10 April 2023, Shift 2, Physics Q40

Question 40 of 90 in this shift, Physics question 10 of 30, Section A.

A person travels xx distance with velocity v1v_1 and then xx distance with velocity v2v_2 in the same direction. The average velocity of the person is v, then the relation between v, v1v_1 and v2v_2 will be.
  1. (1)v=v1+v22v = \frac{v_1 + v_2}{2}
  2. (2)v=v1+v2v = v_1 + v_2
  3. (3)1v=1v1+1v2\frac{1}{v} = \frac{1}{v_1} + \frac{1}{v_2}
  4. (4)2v=1v1+1v2\frac{2}{v} = \frac{1}{v_1} + \frac{1}{v_2}Official answer

Official answer

Option 4

NTA final key.