JEE Main 2023 · MathsNumerical answerNumerical valueMediumCalculation

JEE Main 10 April 2023, Shift 2, Maths Q26

Question 26 of 90 in this shift, Maths question 26 of 30, Section B.

If the area of the region

\{(x, y) : |x^2 - 2| \leq y \leq x\}

is A, then

6A + 16\sqrt{2}

is equal to ______.

Official answer

NTA final key.

Chapter: Application of Integrals
Topic: Area Under Curves
Idea tested: Area with Modulus

Same idea in other shifts

Asked 7× in all

2 Apr 2025, Shift 1 · Q21If the area of the region $\left\{(x, y): \left|4-x^2\right|\le y\le x^2,\ y\le4,\ x\ge0\right\}$ is…HardNumerical value
5 Apr 2024, Shift 2 · Q12The area enclosed between the curves $y = x|x|$ and $y = x - |x|$ is :MediumSingle correct
6 Apr 2023, Shift 2 · Q14The area bounded by the curves $y=|x-1|+|x-2|$ and $y=3$ is equal toEasySingle correct
26 Jul 2022, Shift 2 · Q20The area bounded by the curves $y=|x^2-1|$ and $y=1$ isMediumSingle correct
29 Jul 2022, Shift 1 · Q16The area of the region $\{(x, y) : |x - 1| \leq y \leq \sqrt{5 - x^2}\}$ is equal to :MediumSingle correct
28 Jun 2022, Shift 2 · Q9The area of the bounded region enclosed by the curve $y=3-\left|x-\frac{1}{2}\right|-|x+1|$ and the $x$ -axis is :MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.