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Saturday, 31 October

JEE Main 2023 · ChemistryNumerical answerNumerical valueMediumCalculation

JEE Main 10 April 2023, Shift 1, Chemistry Q86

Question 86 of 90 in this shift, Chemistry question 26 of 30, Section B.

FeO42−→+2.2 VFe3+→+0.70 VFe2+→−0.45 VFe0\mathrm{FeO_4^{2-}} \xrightarrow{+2.2\,\mathrm{V}} \mathrm{Fe^{3+}} \xrightarrow{+0.70\,\mathrm{V}} \mathrm{Fe^{2+}} \xrightarrow{-0.45\,\mathrm{V}} \mathrm{Fe^{0}} EFeO42−/Fe2+0E^{0}_{\mathrm{FeO_4^{2-}/Fe^{2+}}} is x×10−3x \times 10^{-3} V. The value of xx is ___________

Official answer

1825

NTA final key.

Same idea in other shifts

Asked 2× in all
  1. 28 Jun 2022, Shift 2 · Q84For the given reactions Sn2++2e−→Sn\mathrm{Sn^{2+} + 2e^- \rightarrow Sn} Sn4++4e−→Sn\mathrm{Sn^{4+} + 4e^- \rightarrow Sn} the electrode potentials are ;…HardNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.