JEE Main 2023 · MathsMultiple choiceSingle correctMediumApplication

JEE Main 8 April 2023, Shift 2, Maths Q5

Question 5 of 90 in this shift, Maths question 5 of 30, Section A.

If the number of words, with or without meaning, which can be made using all the letters of the word MATHEMATICS in which C and S do not come together, is

(6!)k

, then

k

is equal to

(1)945
(2)1890
(3)2835
(4)5670Official answer

Official answer

Option 4

NTA final key.

Chapter: Permutations and Combinations
Topic: Permutations and Combinations
Idea tested: The Block/Tie Method

Same idea in other shifts

Asked 3× in all

4 Apr 2026, Shift 1 · Q8The number of ways, of forming a queue of $4$ boys and $3$ girls such that all the girls are not together, is:EasySingle correct
6 Sep 2020, Shift 2 · Q72The number of words (with or without meaning) that can be formed from all the letters of the word "LETTER" in which vowels never come…MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.