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Saturday, 31 October

JEE Main 2023 · MathsMultiple choiceSingle correctMediumCalculation

JEE Main 6 April 2023, Shift 2, Maths Q10

Question 10 of 90 in this shift, Maths question 10 of 30, Section A.

If gcd (m,n)=1(m, n)=1 and 12−22+32−42+⋯+(2021)2−(2022)2+(2023)2=1012 m2n1^2-2^2+3^2-4^2+\cdots+(2021)^2-(2022)^2+(2023)^2=1012\,m^2n then m2−n2m^2-n^2 is equal to
  1. (1)240240Official answer
  2. (2)220220
  3. (3)200200
  4. (4)180180

Official answer

Option 1

NTA final key.

Chapter
Sequences and Series
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.