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Saturday, 10 October

JEE Main 2023 · ChemistryMultiple choiceDiagram basedHardMulti-step

JEE Main 6 April 2023, Shift 1, Chemistry Q76

Question 76 of 90 in this shift, Chemistry question 16 of 30, Section A.

The major product formed in the following reaction is [Reactant: benzene ring bearing ortho CH2CONH2\mathrm{CH_2CONH_2} and COOCH3\mathrm{COOCH_3} groups] →ΔBr2/NaOH\xrightarrow[\Delta]{\mathrm{Br_2/NaOH}}

The figure, in words

Reactant: benzene ring with ortho substituents CH2-CONH2 and COOCH3; reagent Br2/NaOH, heat.
  1. (1)[figure: benzo-fused five-membered lactam (isoindolin-1-one): ring with CH2, NH and C=O]Official answer
  2. (2)[figure: benzo-fused six-membered cyclic anhydride: ring with CH2, C=O, O, C=O]
  3. (3)[figure: benzo-fused six-membered cyclic imide: ring with CH2, C=O, NH, C=O]
  4. (4)[figure: benzo-fused six-membered carbocyclic 1,3-dione: ring with CH2, C=O, CH2, C=O]

Official answer

Option 1

NTA final key.

Chapter
Amines
Topic
Amines
Idea tested
Hofmann Bromamide Degradation

Same idea in other shifts

Asked 3× in all
  1. 5 Apr 2026, Shift 2 · Q67Given below are two statements : Statement I : Heating benzamide with bromine in an ethanolic solution of sodium hydroxide will give…MediumTwo statements
  2. 8 Apr 2026, Shift 2 · Q68Which statements are True ? A. In Hoffmann bromamide degradation, 4 moles of NaOH and 2 moles of Br2\mathrm{Br_2} are consumed per mole of…MediumOther

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.