JEE Main 2023 · ChemistryMultiple choiceDiagram basedHardMulti-step
JEE Main 6 April 2023, Shift 1, Chemistry Q73
Question 73 of 90 in this shift, Chemistry question 13 of 30, Section A.
Compound P (M.F. ; M.F. = MOLECULAR FORMULA) on treatment with HCl, gives a Filter step: Residue Q and Filtrate; the Filtrate with NaOH gives Oily Liquid R.
Compound P is neutral, Q gives effervescence with while R reacts with Hinsbergs reagent to give solid soluble in NaOH. Compound P is
The figure, in words
Scheme: Compound P (M.F. C14H13ON) --HCl, heat--> Filter -> Residue Q and Filtrate; Filtrate --NaOH--> Oily Liquid R. (M.F. = molecular formula.)- (1)[figure: structure, N-methyl-N-phenylbenzamide: C6H5-C(=O)-N(CH3)-C6H5]
- (2)[figure: structure, 3-(methylamino)benzophenone: C6H5-C(=O)-C6H4-NH-CH3 (meta)]
- (3)[figure: structure, biphenyl bearing -CONH2 and a CH3 on the same ring, both meta to the biaryl bond]
- (4)[figure: structure, 4-methyl-N-phenylbenzamide: H3C-C6H4-C(=O)-NH-C6H5 (para)]Official answer
Official answer
Option 4
NTA final key.
- Chapter
- Amines
- Topic
- Amines
- Idea tested
- Hinsberg Test